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The the rate of change of the water level can be converted to an equivalent rate of change in gas volume by multiplying the trendline's slope by the cross-sectional area of the bubble collector:

{latex}
$$
\frac{\Delta Volume}{\Delta Time} = slope * \pi * r _{collector} ^2
$$
{latex}

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!Gas removal, mL-L. GB, 40, 30.png|width=300px!
h5. Figure 3:  Dissolved gas removal for various filter media. Bed Expansion: 50%
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To determine how much gas is removed per liter of water sent through the filter column, that volume rate of change is then divided by the flow rate of water in L/min.

{latex}
$$
\frac{mL\:gas\:removed}{L\:water\:treated} = \frac{\frac{\Delta Volume}{\Delta Time}}{Q_{water}}
$$
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{latex}

This was done for each sand, and the results are plotted in #Figure 2.

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