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  • Mathematical Model: We will look at the governing equations, boundary conditions, initial field velocity function of the jet as well as the formula for calculating Stokes number in this case.
  • Expected Results: We will discuss the expected results from this simulation and compare the numerical results with the expected results.

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Wiki Markup
{latex}
\begin{align*}
Re \equiv \frac{\rho d_p |\overrightarrow{u_p}-\overrightarrow{u}|}{\mu}
\end{align*}
{latex}

Initial Field Velocity Function

The initial field function setup of a jet is essentially two shear layers. The two shear layers are symmetrical to the centerline. A hyperbolic tangent velocity function is used to initialize velocity field of a shear layer. The hyperbolic tangent velocity functions are preferred over discontinuous piecewise functions because hyperbolic tangent functions are more physical. The initial field velocity function for the entire jet is given below:

Wiki Markup
{latex}
\[
u_{initial}(y) =
\left\{
  \begin{array}{lr}
    tanh(32y-8) & : 0 \leq x \leq 0.5\\
    -tanh(32y-24) & : 0.5n < n \leq 1
  \end{array}
\right.
\]
{latex}

     

Wiki Markup
{latex}
\begin{align*}
&V_{initial} = 0\\
&\text{Tip:}\\
&tanh(x)=\frac{e^x-e^{-x}}{e^x+e^{-x}}\\
\end{align*}
{latex}

The function is plotted below (x velocity versus y) using simple MATLAB codes:

Image Added

Stokes Number

The Stokes number is a dimensionless number that corresponds to the behavior of particles suspended in a fluid flow. The Stokes number is defined as below:

Wiki Markup
{latex}
\begin{eqnarray*}
Stk = \frac{\tau U_0}{d_c}  (1)
\end{eqnarray*}
{latex}

Wiki Markup
{latex}$\tau${latex}
 is the relaxation time of the particle, 
Wiki Markup
{latex}$U_0${latex}
 is the fluid velocity well away from the particle, and 
Wiki Markup
{latex}$d_c${latex}
 is the characteristic length scale of the obstacle, in this case it is the diameter of the particle.

Thus: 

Wiki Markup
{latex}$d_c = d_p = d${latex}  (2)
In the case of Stokes flow, where the Reynolds number is sufficiently small the relaxation time can be expressed using the equation below:

Wiki Markup
{latex}
\begin{align*}
&\tau = \frac{\rho_d d_d ^2}{18 \mu_g} \\
\end{align*}
{latex}

Expected Results

Note

Under Construction

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