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Verification and Validation
Total Deformation
In the last section, we found the max deflection at the tip of the crank to be about 0.05 in for the specified loading condition. Back in the pre-analysis we had predicted this max deflection to be around 0.04 in. Our results agree pretty well considering that we had simplified the calculation for deflection by essentially using one guess height instead of accounting for the variable height along the x-direction which would have been much more complex. We are therefore confident that our result from the ANSYS simulation is in the right ball park.
...
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{latex}$\sigma_x${latex} |
...
...
the
...
height
...
of
...
the
...
cross-section
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Now
...
that
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we
...
found
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normal
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stress
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along
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the
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y-direction
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of
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the
...
cross
...
section
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(i.e
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on
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the
...
path),
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we
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can
...
compare
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these
...
results
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with
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Euler-Bernoulli
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beam
...
theory.
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Remember
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that
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back
...
in
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the
...
...
,
...
we
...
determined
...
that
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it
...
would
...
be
...
sufficient
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to
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simply
...
comparing
...
our
...
results
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at
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the
...
top
...
of
...
the
...
gauge
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only.
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Also
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remember
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that
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the
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value
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found
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in
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the
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hand-calculation
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actually
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came
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from
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a
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height
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value
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that
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we
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had
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approximated
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from
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the
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crank
...
diagram.
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Well
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now
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that
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we
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have
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our
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model
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in
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ANSYS,
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we
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can
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find
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what
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the
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height
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truly
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is
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using
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the
...
coordinates
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tool.
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We
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find
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the
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total
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height
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at
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the
...
middle
...
of
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the
...
crank
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to
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be
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0.662
...
in
...
and
...
therefore
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the
...
new
...
coordinates
...
representing
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the
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middle
...
top
...
of
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the
...
gauge
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to
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be
...
(2.448",
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0.331")
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from
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the
...
left
...
whole
...
center.
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Calculating
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{latex}$\sigma_x${latex} |
...
...
this
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revised
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height
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yields
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-12,287
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psi.
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When
...
comparing
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this
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value
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with
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ANSYS,
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we
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find
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our
...
results
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to
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match
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extremely
...
well
...
!
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ANSYS |
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...
Result |
|---|
...
Hand-Calculation |
|---|
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Result |
|---|
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Percent |
|---|
...
Difference |
|---|
-12,761 |
...
psi |
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-12,212 |
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psi |
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4.4% |
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