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Now, in the outline window, click Solution > Sigma-r. This will bring up the stress distribution for the stress in the r-direction.

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Looking at the distribution, we can see that the stress varies only as a function of r as expected. Also, we can see that there seems to be some sort of stress concentrations in the are where the moment was applied. In our analysis, we ignored these transient stresses, but it is important to know that ANSYS calculated them when we try to obtain the solution to the problem statement. In order to further examine the stresses in the r-direction, lets look at an area far from the transient stresses in order to minimize their effect on the computational solution. Click on Solution > Sigma-r without transience. This solution is the stress in the r-direction at the midpoint of the beam. This line is far enough from the moment that the transient stresses will not affect its local stresses.

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Click the Max and Min Tags in the menu bar: they will show the maximum and minimum stresses and their locations. Now, we can see that the maximum r-stress is -.110 psi, and the minimum r-stress is -82.302 psi.

Sigma-theta

Now click Solution > Sigma-theta in the outline window. This will bring up the stress distribution for the stress in the theta direction.

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As with Sigma-r, the stress is a function of r, only. Also, there is some transience near the moment. Again, we will look at an area of the geometry far from the moment to decrease the transience's influence on our solution. Click Solution > Sigma-theta without transience in the outline window to bring up the stress distribution at the middle of the bar.

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In the details window, click Solution > Tau-r-theta to bring up the stress distribution for shear stress.

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Now that we have a good idea about the stress distribution, we will look specifically at solving the problem in the problem specification. First, we will look at the stress in the r-direction at r = 11.5 inches. In the outline window, click Solution > Sigma-r at r =11.5. This will bring up the stress in the r-direction along the path at r = 11.5 inches (from the center of curvature of the bar).

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Now, we will do the same for the stress in theta direction to determine sigma-theta at r = 11.5 inches. In the outline window, click Solution > Sigma-theta at r =11.5. This will bring up the stress in the theta-direction along the path at r 11.5 inches.

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Finally, we will examine the shear stress at r = 11.5 in. In the outline window, click Solution > Tau-r-theta at r =11.5. Again, look at the bottom of the table. You will find that the shear stress is very small at this point as we mentioned above.