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Tensile Bar (Results-Interpretation) - Panel
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If equations below don't display properly and you get a "latex plugin" error, please refresh the page.

Pre-Analysis and Start-Up

In the Pre-Analysis step, we'll review the following:

  • Mathematical model: We'll look at the governing equations + boundary conditions and the assumptions contained within the mathematical model.
  • Hand-calculations of expected results: We'll use an analytical solution of the mathematical model to predict the expected stress field from ANSYS. We'll pay close attention to additional assumptions that have to be made in order to obtain an analytical solution.
  • Numerical solution procedure in ANSYS: We'll briefly overview the solution strategy used by ANSYS and contrast it to the hand calculation approach.

Mathematical Model

We'll first list the assumptions in the mathematical model. Then, we'll review the governing equations and boundary conditions that form the mathematical model. Note that this type of a mathematical model where you have a set of differential equations together with a set of additional restraints at the boundaries is called a Boundary Value Problem (BVP). A lot of practical problems that are solved using ANSYS and other FEA software are BVP's. You should have encountered simple BVP's in your math courses, problems of the kind that involve solving a differential equation with a set of boundary conditions (I was never good at these math problems and it showed in my math grades to the displeasure of my parents .... fortunately that is now a distant memory!). You can think of the BVP considered in this tutorial as a souped-up version of simpler BVP's you have encountered in math courses (and either liked or hated!).

Assumptions

We'll assume that:

  1. Plane stress conditions apply since the bar is thin, thus we don't expect significant variation of stresses in the z direction: 

    Latex
    \begin{align*}
    \sigma_{z

...

  1. } = \tau_{xz} = \tau_{yz} = 0
    \

...

  1. end{

...

  1. align*}
  2. Gravity effects can be neglected i.e.

...

  1. no

...

  1. body

...

  1. forces.

...

  1.  

    Latex
    \begin{align*}
    F_x = F_y =0
    \

...

  1. end{align*}

Governing Equations

Since we are assuming plane stress conditions, we can use the 2D version of the equilibrium equations. When the deformed structure reaches equilibrium, the 2D stress components should satisfy the 2D equilibrium equations with zero body forces:

Latex
\begin{align* of the bar is assumed to equal zero.
{latex}
\begin{eqnarray}
U = V = 0\nonumber
\\
at\nonumber 
\\
x = 0\nonumber
\end{eqnarray}
{latex}

h5. Additional Assumptions

Since the length is much larger than the width, we ignore end effects and neglect stress variations in the y direction.

Because they are free surfaces, stress in the y direction equals zero at both the top (y = H) and bottom (y = 0) surfaces of the bar.  
If a surface is not constricted and can move freely, it can expand and contract without incurring stress.

All regions other than the ends, are in a pure uniaxial stress, thus stress in the y direction and shear in the xy direction equals zero.
{latex}
\begin{eqnarray}
\sigma_y = \tau_{xy} = 0\nonumber
\end{eqnarray}
{latex}



h5. Governing equations

Since we are assuming plane stress conditions, we can use the 2D version of the equilibrium equations. When the bar is in equilibrium, the stresses will satisfy the 2D equilibrium equations with no body forces.

{latex}
\begin{eqnarray}
{\partial \sigma_x \over \partial x} + {\partial \tau\_{yxxy} \over \partial y} + 0 = 0 \nonumber
\\
{\partial \tau\_{xy} \over \partial x} + {\partial \sigma_y \over \partial y} + 0 = 0 \nonumber
\end{eqnarray}
{latex}

h5. Boundary Conditions

The domain over which we'll solve the governing equations is a rectangle.

((Equation and Figure))

The boundary conditions are:

{latex}
\begin{eqnarrayalign*}

 

Boundary Conditions

We solve these equations in a rectangular domain and impose the appropriate boundary conditions. At every point on the boundary, either the displacement or the traction must be prescribed.

Image Added

The bottom and top edges are free. If a boundary location is not constrained and can move freely, it can expand and contract without incurring stress. Thus, traction on the free edges is zero and we get 

Latex
\begin{align*}
\sigma_y = \tau_{xy} = 0\nonumber \:\: at \: y = 0 \: and \: y = H
\end{eqnarray}
{latex}


\\
\\

h3. Solving the BVP

First, we apply the assumption that tau_xy = 0, thus the equilibrium equation in the x-direction becomes:
{latex}
\begin{eqnarray}
{\partial \sigma_x \over \partial x} = 0\nonumber
\end{eqnarray}
{latex}


Therefore,
{latex}
\begin{eqnarray}
\sigma_x = constant\nonumber
\end{eqnarray}
{latex}

Apply Boundary Conditions: If we make a vertical cut in the geometry, then the stress must be P/A. Therefore,
\\
{latex}
align*}

 

The left end is fixed. So both components of displacement are zero at this end:

Latex
\begin{align*}
u = v = 0 \:\: at \: x = 0
\end{align*}

 

The boundary condition is a little bit more complicated at the right end. Here, the traction is specified at the mid-point where the point load is applied. The applied traction at all other points on the right boundary is zero. For brevity, we won't write out the corresponding equations at the right boundary. We'll simplify this boundary condition in our hand calculations below (to make the problem tractable) but the ANSYS solution provided uses the full set of boundary conditions. Another complication is that since we have a point load, the specified traction at the mid-point of the right end is infinite. We'll later discuss the effect of this in the ANSYS solution. Do keep in mind that there are no point loads in practice, it's just an idealization that can lead to weird behavior that we need to be aware of.

Hand Calculations

Now that we have reviewed the mathematical model for our problem, let's hold off diving into ANSYS just yet and first make some hand calculations of expected results. We'll use these hand calculations to check ANSYS results (like an expert engineer would!). In order to make the problem solvable by hand, we need to make additional assumptions. The ANSYS solution does not make these additional assumptions.

Additional Assumptions in Hand Calculations

  1. We'll simplify the right boundary condition. Instead of a point load, we'll assume that the load is distributed over the entire right boundary. So the traction condition at the right boundary becomes

    Latex
    \begin{align*}
    \sigma_x = P/(H \, t), \: \: \tau_{xy} = 0 \: \: \: at \: x = L
    \end{align*}

    Here, t is the thickness.
    The following schematic shows the process of simplifying the right boundary condition in the hand calculation.


    Image Added

  2. Away from the left and right ends, we expect a uni-axial state of stress with zero shear (OK, this is a bit of a leap of the imagination but it's plausible). So we'll assume that everywhere

    Latex
    \begin{align*}
    \tau_{xy} = 0
    \end{align*}

    We don't expect this to hold near the left boundary or in the vicinity of the point load, so our hand calculations won't be valid there.

Analytical Solution

With these additional assumptions in hand, we can easily solve the BVP and we get the following analytical solution:

Latex
\begin{align*\begin{eqnarray}
\sigma_x = P/A(H \, t), \: \: \: \sigma_y = 0
\end{eqnarrayalign*}

 

This is the well known (P/A) result but we have arrived at it somewhat carefully, accounting for the additional assumptions we made in the process. We'll need to keep these additional assumptions in mind when comparing the hand calculations with the ANSYS solution. For the values given in the problem statement, we have

Latex
\begin{align*}
{latex}
 This is of course a well-known result. For this problem, we have
\\
{latex}
\begin{eqnarray}
\sigma_x = 2000/(10*1) = 200 \ N/mm^2 = 200 \ MPa
\nonumber
\end{eqnarray}
{latex}

h3. Numerical Solution using FEA

In the numerical solution using FEA, we solve the 2D BVP directly by dividing the structure into small elements and approximating the solution for these small elements. Unlike the analytical approach, we do not assume that there is no variation in the y direction. Also, end effects are not neglected. The FEA solution is an approximate solution to the 2D BVP. The approximation gets better as the elements become smaller. In contrast, the analytical solution presented above is the exact solution to the 1D BVP obtained by making approximations to the 2D BVP. In other words, in the analytic solution, we have swapped the actual 2D BVP problem for a 1D BVP problem that we can solve in closed form. Both approaches have value in engineering and complement each other. We have checked that the FEA solution presented to you is reasonably accurate.
\\

The following figure summarizes the contrasts between the analytical and numerical approaches.


!Tensile Bar breakdown small.png!\\

h4. Load FEA Solution obtained using ANSYS

As mentioned before, we are providing the FEA solution obtained using ANSYS so that you can focus on comparing the analytical and numerical solutions (which is the goal of this exercise). Without further ado, let's download the ANSYS solution and load it into ANSYS.

1. Download "Tensile Bar Demo.zip" by [clicking here|Tensile Bar - Pre-analysis and Start-up^Tensile Bar demo.zip]
The zip should contain a _Tensile Bar Demo_ folder with the following contents:
\- Tensile Bar Demo_files folder
\- Tensile Bar Demo.wbpj
Please make sure both these are in the folder, otherwise the solution will not load into ANSYS properly.  (Note: The solution provided was created using ANSYS workbench 13.0 release, there may be compatibility issues when attempting to open with other versions). Be sure to extract before use.

2. Double click "Tensile Bar Demo.wbpj" - This should automatically open ANSYS Workbench (you have to twiddle your thumbs a bit before it opens up). You will then be presented with the ANSYS solution in the project page.
!tensile_bar_wb.jpg!
A tick mark against each step indicates that that step has been completed.

3. To look at the results, double click on {color:purple}{*}{_}Results{_}{*}{color} \- This should bring up a new window (again you have to twiddle your thumbs a bit before it opens up).

4. On the left-hand side there should be an _Outline_ toolbar. Look for {color:purple}{*}{_}Solution (A6)_{*}{color}.

!tensile_bar_outline.jpg!
We'll investigate the items listed under Solution in the next step of this tutorial.
\\

*[Go to Step 2: Numerical Results|Tensile Bar - Numerical Results]*

[Go to all ANSYS Learning Modules|ANSYS Learning Modules]align*}

 

The corresponding strain in the x-direction can be calculated from Hooke' law:

Latex
\begin{align*}
\epsilon_x = \frac{\sigma_x}{E} - \nu \, \frac{\sigma_y}{E} = 1 \times 10^{-6}
\end{align*}

 

The strain is tiny since the material is very stiff with an Young's modulus of 200 GPa. The displacement at the right end can be estimated by integrating the constant x-strain:

Latex
\begin{align*}
\epsilon_x = \frac{\partial u}{\partial x}
\end{align*}
Latex
\begin{align*}
u(x=L) = \int_0^L{\epsilon_x} \, dx = 0.05 \, mm
\end{align*}

 

The above hand calculations give us expected values of stress, strain and displacement which we'll compare with the ANSYS results.

Numerical Solution Procedure in ANSYS

The type of numerical solution procedure used by ANSYS is called finite-element analysis (FEA) or finite-element method (FEM). In FEA, we divide or "discretize" the domain into small rectangles or "elements" (hence the name finite element analysis). ANSYS obtains the numerical solution to the BVP in the discrete domain. ANSYS directly solves for the u and v displacements at selected points called "nodes". Everything else such as the stress variation is derived from these nodal displacements through interpolation. The nodes in our case are the corners of the elements as shown below. As you can imagine, the numerical solution should get better as you increase the number of elements.

Image Added

The following figure summarizes the contrasts between the hand calculations and ANSYS's approach. One important point to keep in mind is that both start with the same mathematical model but use different assumptions and approximations to solve it. Also, in FEA, one always computes the displacement first and from that derives the stress. Contrast that to the hand calculations where we calculated the stress first and from that derived the displacement. The latter process works only for a few simple problems.

Image Added

This brings us to the end of the Pre-Analysis section.

Start-Up: Load Solution into ANSYS

As mentioned before, we are providing the ANSYS solution so that you can focus on comparing the hand calculations with the ANSYS results (which is the goal of this exercise). Without further ado, let's download the ANSYS solution and load it into ANSYS.

1. Download "Tensile Bar Demo.zip" by clicking here
Unzip the file at a convenient location. You will see a folder called Tensile Bar Demo with the following contents:

  • Tensile Bar Demo_files (this is a folder)
  • Tensile Bar Demo.wbpj

Please make sure both these objects are in the unzipped folder, otherwise the solution will not load into ANSYS properly. (Note: The solution provided was created using ANSYS workbench 13.0 release, there may be compatibility issues when attempting to open with older versions).

2. Double click "Tensile Bar Demo.wbpj" - This should automatically open ANSYS Workbench (you have to twiddle your thumbs a bit before it opens up). You will then be presented with the ANSYS solution in the project page.
Image Added
A tick mark against each step indicates that that step has been completed.

3. To look at the results, double click on Results - This should bring up a new window (again you have to twiddle your thumbs a bit before it opens up).

4. On the left-hand side there should be an Outline toolbar. Look for Solution (A6).

Image Added
We'll investigate the items listed under Solution (A6) in the next step of this tutorial.

Go to Step 2: Numerical Results

Go to all ANSYS Learning Modules