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Bike Crank - Panel
Bike Crank - Panel

Pre-Analysis & Start-Up

Pre-Analysis

In the pre-analysis step, we review the:

  • Mathematical model

  • Numerical solution strategy

  • Hand calculations of expected results

Governing Equations

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Additional Equations

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Traction at the Boundary

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Boundary Conditions

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Numerical Solution Strategy

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Hand Calculations

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h1. Pre-Analysis & Start-Up


h2.

h2. Pre-Analysis


h3. Total Deformation

The first back-of-the envelope calculation that we will make is for the total deformation of the crank under the specified applied load. A list of different cantilevered beam loading cases along with their closed-form maximum deflections formulas can be accessed on this link. Because our beam is loaded at the second hole instead of at the tip, our loading is best represented by the case 2 presented (i.e for a cantilevered beam with a concentrated load, P, at any point). The appropriate formula for the maximum deflection is therefore
{latex}
\begin{equation*}
\delta_{max} = -\frac{Pa^{2}}{6EI}(3L-a)
\end{equation*}
{latex}

where "P" is the load, "a" is the distance from the support to the load, "L" is the distance from the support to the end of the beam, "E" is Young's Modulus and "I" is the moment of inertia.

Using the dimensions provided below, we can determine "a" to be 6.69 in and "L" to be 7.674 in.&nbsp;


[!Screen Shot 2014-06-13 at 1.28.46 PM.png|width=450!|^Screen Shot 2014-06-13 at 1.28.46 PM.png]

We also know that "P" is 100 lbs and "E" is 10,000 ksi. The tricky part is to determine the moment of inertia. Recall that for a rectangular cross-section of height h and depth b,&nbsp;

{latex}
\begin{equation*}
I = \frac{1}{12}bh^{3}
\end{equation*}
{latex}

where "h" is the height and "b" is the depth. In this case we know that the depth is 0.375 in but what should we do about this varying height? Since height varies as a function of x, the moment of inertia also varies with x. Finding the maximum deflection for a varying moment of inertia is actually very complex. The goal here is not necessarily to get the exact answer but to get a reasonable idea of what we should expect our ANSYS solution to be.

One simplified approach is to estimate a reasonable average beam height in order to proceed with the moment of inertia calculation. From the diagram above, the maximum height is 2*0.984 = 1.968 in. The minimum height can be approximated as 2*(1.29-0.984) = 0.612 in  if one subtracts the radius of the left circle from the ellipse (the ellipse makes the curvature). From the maximum and minimum heights, we find that the average beam height is 1.29 in. But you and I know that greater deflection arises from the thinner part of the crank and so using the average beam height will likely undershoot the actual maximum deflection. So let us take a value for h that is slightly below the average beam height, say 1 in.

We now have all variables needed to find the maximum deflection. Using equations 1 and 2, we find that our max deflection estimate is 0.039 inches.



h3. {latex}$\sigma_x${latex} along the height of the cross-section


{note}Under Construction{note}


h2. Start-Up


h3.

The following video shows how to launch ANSYS Workbench and choose the appropriate analysis system (which, under the hood, sets the governing equations that one will be solving). The video also shows how to add a new material to the material list for this project. We'll later assign our material to the model in the [Physics Setup|Bike Crank - Physics Setup] step.
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[*Go to Step 2: Geometry*|Bike Crank - Geometry]

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Check Your Understanding

Which one of the following assumptions is contained in the strain-displacement relations in the mathematical model that we will solve using ANSYS? (See edX module for answer)

a. Acceleration at any point in the structure is zero

b. Material is in the elastic range

c. Material is isotropic

d. Strains are small

e. All of the above


Go to Step 2: Geometry

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