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In order to calculate the energy dissipation rate at the rapid mix due to the tubing, first we calculated the head loss (h) of the tubing using the equation,
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{latex} \large $$ h = \left( {{Q \over {ka}}} \right)^2 {1 \over {2g}} $${latex} |
Then we calculated the residence time (θ) using,
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{latex} \large $$ \theta = {{d_{tube} } \over v} $${latex} |
Where,
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{latex} \large $$ v = {Q \over a} $${latex} |
Finally energy dissipation (ε) was calculated using the following equation,
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{latex} \large $$ \varepsilon = {{gh} \over \theta } $${latex} |
Where:
h= the head loss due the tube,
Q = is the flow rate in mL/min
a = the area of the tube
k = constant magnitude of 0.6
g = gravity
θ = the residence time
dtube = the length of energy dissipation of the jet, which was estimated on the length scale of the diameter of the tubing.
V = speed the flow
ε = energy dissipation
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