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In order to calculate the energy dissipation rate at the rapid mix due to the tubing, first we calculated the head loss (h) of the tubing using the equation,

{latex}
\large

$$
h = \left( {{Q \over {ka}}} \right)^2 {1 \over {2g}}
$${latex}

{latex}
\large

$$
\theta = {{d_{tube} } \over v}
$${latex}

Where,

{latex}
\large

$$
v = {Q \over a}
$${latex}

{latex}
\large

$$
\varepsilon = {{gh} \over \theta }
$${latex}

Where:

h= the head loss due the tube,
Q = is the flow rate in mL/min
a = the area of the tube
k = constant magnitude of 0.6
g = gravity
θ = the residence time
d_{tube =} the length of energy dissipation of the jet, which was estimated on the length scale of the diameter of the tubing.
V = speed the flow
ε = energy dissipation

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