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The the rate of change of the water level can be converted to an equivalent rate of change in gas volume by multiplying the trendline's slope by the cross-sectional area of the bubble collector:
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{latex} $$ \frac{\Delta Volume}{\Delta Time} = slope * \pi * r _{collector} ^2 $$ {latex} |
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{float:right|border=2px solid black|width=300px} !Gas removal, mL-L. GB, 40, 30.png|width=300px! h5. Figure 3: Dissolved gas removal for various filter media. Bed Expansion: 50% {float} |
To determine how much gas is removed per liter of water sent through the filter column, that volume rate of change is then divided by the flow rate of water in L/min.
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{latex} $$ \frac{mL\:gas\:removed}{L\:water\:treated} = \frac{\frac{\Delta Volume}{\Delta Time}}{Q_{water}} $$ \\ {latex} |
This was done for each sand, and the results are plotted in #Figure 2.
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